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Ok, i tested it again, and this are my results These one fails always (command can not be found) echo{ echo} echo) echo^ echo! echo' echo` echo~ EDIT: I fixed some incorrect description, see also Discussion about jeb's batch parsing rules on StackOverflow These one fails, if files exists like echo*....

Why this works? Well, I don't know it exactly. Seems that normal variables will expand before the line is processed by cmd.exe Yes, the expansion of ! is nearly the latest interpreter phase for a line. I have made some experiments ... The phasese are: Expanding of %var% Parse the first two tokens o...

I suggest that if a character is acceptable to Windows as being part of a file name, then that character cannot be safely used as a "suffix" to ECHO, otherwise CMD.EXE will trawl through the current directory and then the %PATH% trying to find "ECHO+" with an executable extensio...

Hi santhosh,

if you know the content it should be easy


But it will fail if your date has a format like "10/08/2010", the "/" is not allowed as (directory-)name.

It only works on an english version, because you get something like "current date is 10/08/2010" "Enter new date: (DD-MM-YY)" or it also works with "Enter new date: (YY-DD-MM)" but in german you got "Geben Sie das neue Datum ein: (TT-MM-JJ)" So the script can'...

The first is when I write the data ECHO %name% >> "ADDRESS.%newCode1%.%newCode2%" it's add a blank space at the end of line It's because of the space behind %name% You can use ECHO %name%>> "ADDRESS.%newCode1%.%newCode2%" or >> "ADDRESS.%newCode1%.%newCode2%" ECHO %nam...

Hi, the problem: If you want to echo a variable that could be empty you can not use echo %var% because the output is not empty, instead you got "echo is enabled (on)" or something similar. So most people use the echo. trick echo.%var% This works, but fails if you have anywhere in your path...

As you can see I escaped the brackets too, but no success. Any ideas? Yes. It is the ampersand, it is active because the escape for second quote isn't working. (I suppose it is not neccessary to escape the brackets) So the command is splitting set "newstring=^" & (" set "new...

" Zeichen ist kein Problem Ok, at this point it isn't a problem, but next time ... Will do my best. Do you have any suggestions, jeb? That's why the problem is tricky, I believe there is no simple, clean solution. Example string 12>345^6"78^9a>b Because, the first replacement have to be t...

Seems I got it. Sorry, but you didn't Your example is too short This one fails. example.txt UEME_RUNPATH:C:\Program Files\myProggy\ &()[]{}^=;!'+,`~-_><|*?%$/.@"#0123 "&()[]{}^=;!'+,`~-_><|*?%$/.@"#0123 ")" kann syntaktisch an dieser Stelle nicht verarbeitet werden....

call set S_%%a=%%n%% REM what does here exactly happen or set "char=%char:^=^^%" REM same as above... The first line is a simple set of the variables named S_a, S_B, S_c,... with the values 0, 1, 2, ... It is the same like set S_a=0 set S_b=1 set S_c=2 The second line is a replacement fun...

ByteAnalyser wrote:---::[ NoteS ]::---
Just again some comments or info about "very special" functions or characters used...

Are you interested in "very special" functions or do you have a question about one of your functions?

Or you can use it like



Also, you can read about it with set /?

You got problems, because numbers with prefixed "0" are interpreted as octal numbers

A simple way is to prepend a "1" to the number and then remove it mathematical.

It is a litte bit tricky. @echo off setlocal EnableDelayedExpansion set line=abcde1234fghil set Rec1=5 set Rec2=4 call set var1=%%line:~%Rec1%,%Rec2%%% echo var1=%var1% set var2=!line:~%Rec1%,%Rec2%! echo var2=%var2% Variant1 works because after the first expansion you got call set var1=%line:~5,4% ...