Batch file for telnet output to .txt file

[Abhi]

Hi,

I am trying to create a batch file , that show me the result on txt file for port available/ not available using telnet ...

@echo off
telnet 192.168.0.173 9091
if !%errorlevel%==! goto error1

ELSE
( goto error2)

:error1
echo TELNET_Success >> D:\host1_%date%.txt

:error2
echo TELNET_fail >> D:\host1_%date%.txt



but its not working ....in both case it is showing same result ...

Guys pls help

[penpen]

I'm not sure if telnet sets the errorlevel in that way.
You have to add some goto's to avoid processing both echoes to file.
In addition the syntax of the for else is not right.
Maybe this works (if telnet sets the errorlevel):

Code: Select all

@echo off
telnet 192.168.0.173 9091 
if %errorlevel% == 0 goto :error1
goto :error2

:error1
echo TELNET_Success >> D:\host1_%date%.txt
goto :eof

:error2
echo TELNET_fail >> D:\host1_%date%.txt
goto :eof

penpen

[foxidrive]

This uses the free Telnet Scripting Tool v.1.0 by Albert Yale

Code: Select all

@echo off
:: The format is: remote.domain.com port
set host=ftp.domain.com 21
(
echo %host%
echo WAIT "\m"
echo SEND ""
)>"%temp%\tst.script"

tst10.exe /r:"%temp%\tst.script" /o:"%temp%\tst.info" /m
for %%a in ("%temp%\tst.info") do if %%~za EQU 0 (echo %host% not responding) else (echo %host% is up)
pause