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Hi all,
Could someone give me an easy-to-understand overview of the set /a command?
Preferably with an example.

Thanks,
Rileyh

Rileyh wrote:Hi all,
Could someone give me an easy-to-understand overview of the set /a command?
Preferably with an example.

Thanks,
Rileyh

"set" is used to define variables. "set /a" just views your variable as an equation and tries to solve it. Such as



will return "10".

Further to the original question, I am struggling with certain aspects of the set /a command. Below is copied from Win 7 command window help for set.
() z z z z z z z z z - grouping
! ~ - z z z z z z z - unary operators ! what is it
* / % z z z z z z z - arithmetic operators
+ - z z z z z z z z - arithmetic operators
<< >> z z z z z z - logical shift << >> how to use them
& z z z z z zz z z z - bitwise and
^ z z z z z z z z z - bitwise exclusive or
| z z z z z z z z z - bitwise or
= *= /= %= += -= - assignment = I understand but what are the rest and how to use
&= ^= |= <<= >>= - assignment what are these and how to use
, z z z z z z z z z z z - expression separator how to use
I don't understand what some of these are and how to use them. Some help would be great. See my comments to the right in red. It looks a bit messy but you should have seen it before I padded some of the lines with z z z z z z .

Pretty sure '!' means 'not'. In a different scripting language it was like this tho:



Basically means if variable 1 is not equal to variable 2 the do something

With a bit of looking round Wikipedia and some experimentation I have worked out the answers to all of my questions about the batch operators except the unary ! I cant seem to use it and get a meaningful result. The big problem is I am not sure what it is. Is it a logical NOT or a ones complement (bitwise inversion). Exouxas ventures out and suggests it as a comparison operator but that does not work (for me). The batch IF already has the following as comparison operators EQU, NEQ, LSS, LEQ, GTR, GEQ so it would seem to be unnecessary to use others. I have been looking at http://en.wikipedia.org/wiki/Unary_operator and http://en.wikipedia.org/wiki/Negation and I am now bogged down.
edit
I forgot about the expression separator , does nayone have any examples of usage.

Bob D wrote:I have worked out the answers to all of my questions about the batch operators except the unary ! I cant seem to use it and get a meaningful result. The big problem is I am not sure what it is. Is it a logical NOT or a ones complement (bitwise inversion).

The ~ operator provides the one's complement (otherwise known as bitwise negation or bitwise inversion)

The ! operator provides logical negation with a twist: It assumes 0 represents FALSE, and any non-zero value represents TRUE. The result is always expressed as either 0 (FALSE) or 1 (TRUE).
So !(0)=1 and !(non-zero)=0

Bob D wrote:I forgot about the expression separator , does nayone have any examples of usage.

The comma allows multiple assignments in the same statement
output


Dave Benham

Thanks Dave, it all makes sense now. When I was testing the ! I was getting the correct results but I just didn't believe them. Also the info on ~. I had it worked out as twos complement. Thanks for correcting my error. I'm getting there. I haven't done much in higher languages (if you could call Batch that) for about 30 years. So I'm a bit rusty. More recently I have been doing IBM 370 Assembler but I'm rusty on that too as I retired about 10 years back and I haven't been near one of them since.
Bob

Bob D wrote:Also the info on ~. I had it worked out as twos complement.

The - unary operator provides the two's compliment (numeric negation)

Dave Benham

An example for "logical shift":

The output is 28.
Why?
The binary expression for 7 is 111.
Shifting 2 digits to the left results to
11100 (bin) = 28 (dec).

Regards
aGerman

Beware - the HELP for the SET command is wrong with regard to the shift operators

The help states they are logical shift operators when in fact they are arithmetic shift operators. This has a major impact on the right shift of a negative number.

The right shift (>>) fills in with the value of the sign bit such that a negative number always remains negative.
The left shift (<<) always fills in with 0.
Neither operator detects overflow.

example: SET /A "1<<31>>31" yields -1 (all bits set)
If this were true logical shifts then the answer would be 1 (only 1 bit set)

Dave Benham

You're right Dave. I assume logical and arithmetic shift are only the same for the left shift operator.

Regards
aGerman

Some systems differentiate between arithmetic left shift and logical left shift by detecting overflow during arithmetic left shifts.

Without overflow detection, arithmetic and logical left shifts are indeed the same.

Our "DOS" SET /A arithmetic shift operators do not detect overflow.


Dave Benham

For the operations += -= *= /= ...

If you have a variable and used this variable with the operation executed is this a easy way.
i.E.
num=23
num=num+5

The same result
num=23
num+=5

The set /a command can also be used when creating loops.

eg. To write a text file counting from 1 to 100 named numbers write:

NOTE: the variable can't equal zero, thus must start at 1, and the if parameter must be set 1 greater than desired stopping point.

The variable can equal 0 if you would write the redirection in an opposite way:

Also there is an operator += to increment a number:

BTW: A FOR /L loop would be a better solution.

Regards
aGerman