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Hi, i am looking for a windows-batch solution to the problem of, replacing the last occurrence of the given character on each lines of file. the input and the output should be as below:

algorithm:
replace the last "-" on each line with " AAA "

input file:
-some-text-here
some-morehere
blah-blah-
-end

output file:
-some-text AAA here
some AAA morehere
blah-blah AAA
AAA end

Actually i have a unix script to perform the task with sed, wit whom i replace every last / with :/" archives="



Any help will be appreciated, thanks in advance..

Then why not just use sed to do this as well.

hi squashman, because i need a portable and native solution which can run on every windows system without an installation. i need to solve it programmatically, not by installing sed for windows, if possible..
any advice?

thanks.

Will your files have any blank lines, or % ^ ! characters in them?
That is the first hurdle.

Is performance going to be an issue - are the files large?

Those things can make plain batch an issue.

hi foxidrive,

performance is not of a big concern.
my aim is perform such a conversion:

<input.txt>
/data/kibris/AS/lib/Administration.jar
/data/kibris/AS/lib/Extensions.jar
/data/kibris/AS/lib/Batch.jar

<output.txt>
/data/kibris/AS/lib/" archives="Administration.jar
/data/kibris/AS/lib/" archives="Extensions.jar
/data/kibris/AS/lib/" archives="Batch.jar

in other words, i like to parse a fullpath into path and file name and place a string in between. (replacing the last occorrence of / with /" archives=" does the same here.)

about your question; i have no blank lines but have "/" to to be replaced.

kind regards.

You have no idea how different the two requirements you stated are in terms of the required batch code!

Thank you for giving us the real data - this should do what you need.

EDIT:




If you can handle backslashes in the path then this will work:

thank you very much foxidrive, your first code suggested does just what i need.