Replace substring containing spaces

[dfashimpaur]

Hello all.

I am trying to create a DOS file which will modify some string data for me. The input strings can be dynamic and the replacement value may need to be empty (no characters) and sometimes it may be a substring containing spaces.

This is essentially what I have:

Code: Select all

@ECHO off
SETLOCAL ENABLEDELAYEDEXPANSION

SET originalStr="Some text to be processed. Some text may contain Hello World. Some text may contain nothing worthwhile at all."
SET strToReplace="nothing worthwhile at all"
SET replacementString="very important stuff"

:: I thought this would work.... but it does not

SET str=%originalStr:!strToReplace!=!replacementString!%

ENDLOCAL

Is there anyway to get this to work as I want it to?

[Squashman]

Code: Select all

@ECHO off
SETLOCAL ENABLEDELAYEDEXPANSION

SET originalStr="Some text to be processed. Some text may contain Hello World. Some text may contain nothing worthwhile at all."
SET strToReplace=nothing worthwhile at all
SET replacementString=very important stuff

SET str=!originalStr:%strToReplace%=%replacementString%!

echo %str%
pause

ENDLOCAL

[dfashimpaur]

Code: Select all

@ECHO off
SETLOCAL ENABLEDELAYEDEXPANSION

SET originalStr="Some text to be processed. Some text may contain Hello World. Some text may contain nothing worthwhile at all."
SET strToReplace=nothing worthwhile at all
SET replacementString=very important stuff

SET str=!originalStr:%strToReplace%=%replacementString%!

echo %str%
pause

ENDLOCAL

Thanks, Squashman. Will it be a problem if replacementString is empty?

[Squashman]

what is stopping you from answering your own question by at least trying it first.