Find string in a big txt file and rturn the number line where the string is

[sal21]

i'm working with vb6.

possible to:
Find a string in a big txt file and return the number of line where the string is found?
Naturally store the line number in a variable

note:
i need to integrate the batch in my vb6 application

tks and sorry for my bad english.

[aGerman]

Code: Select all

for /f "delims=:" %%i in ('findstr /nc:"your string" "your file.txt"') do set "n=%%i"

... untested though.

i need to integrate the batch in my vb6 application

Any good reason why you don't do this task in VB directly?

Steffen

[sal21]

tks!
Sorry for delay.

but i need to use vb6.

possible to use the VB6 Shell?

If yes, have an idea for vb6 code?
Tks

[sal21]

Code: Select all

for /f "delims=:" %%i in ('findstr /nc:"your string" "your file.txt"') do set "n=%%i"

... untested though.

i need to integrate the batch in my vb6 application

Any good reason why you don't do this task in VB directly?

Steffen

tks!
Sorry for delay.

but i need to use vb6.

possible to use the VB6 Shell?

If yes, have an idea for vb6 code?
Tks

[aGerman]

but i need to use vb6.

I'm not experienced with VB6. This is a Batch forum and I offered a Batch solution...

Steffen

[sal21]

but i need to use vb6.

I'm not experienced with VB6. This is a Batch forum and I offered a Batch solution...

Steffen

ok
i can trap your code in a file .bat?
In this case i know the code in vb6 to lunch the bat.
if is possible, can you integrate your code to return the number of line finded in c:\test\myresult.txt

tks

[aGerman]

Just a guess ...

Code: Select all

@for /f "delims=:" %%i in ('findstr /nc:"your string" "your file.txt"') do exit /b %%i

No idea if that is what "return the number" means in your case.

Steffen

[sal21]

Just a guess ...

Code: Select all

@for /f "delims=:" %%i in ('findstr /nc:"your string" "your file.txt"') do exit /b %%i

No idea if that is what "return the number" means in your case.

Steffen

HI Steffen, TKS FOR CODE.!

To save the result of bat in c:\testdir\result.txt, in this case the number of line found?

is this correct:
@for /f "delims=:" %%i in ('findstr /nc:"your string" "your file.txt"') do exit /b %%i > c:\testdir\result.txt

[aGerman]

No, you have to redirect the ECHO output to the file.

Code: Select all

@for /f "delims=:" %%i in ('findstr /nc:"your string" "your file.txt"') do >"c:\testdir\result.txt" echo %%i

Steffen

[sal21]

No, you have to redirect the ECHO output to the file.

Code: Select all

@for /f "delims=:" %%i in ('findstr /nc:"your string" "your file.txt"') do >"c:\testdir\result.txt" echo %%i

Steffen

Is this correct?

[aGerman]

Does it work?
How should I know the content of your 985.txt and if all paths are correct and existing?

Steffen

[sal21]

Does it work?
How should I know the content of your 985.txt and if all paths are correct and existing?

Steffen

resolved!
wRONG PATH!
tHE CODE NOW WORK PERFECT!

Bro, love Pizza?
When you come in Napoli....

Tks also for your time.
Sal

[sal21]

Does it work?
How should I know the content of your 985.txt and if all paths are correct and existing?

Steffen

OPS.....
in txt file i can have:
AAAA
AAAA
AAAA

The bat capture all AAAA...

in my work i need to capture only the first occurrence of AAAA, and exit from the code, possible?

[aGerman]

Try it this way

Code: Select all

@for /f "delims=:" %%i in ('findstr /nc:"your string" "your file.txt"') do >"c:\testdir\result.txt" echo %%i&exit /b

Steffen