grab specific text from a location in a file.

[chr15b]

Is it possible using findstr or another tool to get unknown text from a known position?


the text i need is always the 11th charactor in a file for 5 charactors.

ie aaaaaaaaaabbbbb

i need to get and use what bbbbb is.

unfortunately this text changes so i'm not able to search on what it is.

Thanks

[Squashman]

If you are parsing a text file with a for Loop you can set the loop variable to another variable and then parse the string by position. Is this unknown text on a specific line in the file? Or is the file just one line long?
http://www.dostips.com/DtTipsStringMani ... .MidString

[chr15b]

Hi, thanks for the reply. The file in question has many many lines but i'm only interested in the first row. the data is unknown but the location is fixed, it is always charactors 11-15

Cheers
Chris

[Ed Dyreen]

'

Code: Select all

@echo off
set "var=aaaaaaaaaabbbbb"
set "var=%var:~10%" %= pos 10 =%
set "var"
pause
set /?
pause

Code: Select all

var=bbbbb

[chr15b]

Thanks for this, presumably i would use findstr to grab the first line - how do i get what it grabs to become a variable as ordinarily it echo's the result?

Thanks

[Ed Dyreen]

'

Code: Select all

>"ou.TMP" echo.testing 1 2 3
<"ou.TMP" set /p "var="
echo.%var%

Code: Select all

testing 1 2 3